26x^2=54

Solution for 26x^2=54 equation:

26x^2=54

We move all terms to the left:

26x^2-(54)=0

a = 26; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·26·(-54)
Δ = 5616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5616}=\sqrt{144*39}=\sqrt{144}*\sqrt{39}=12\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{39}}{2*26}=\frac{0-12\sqrt{39}}{52}
=-\frac{12\sqrt{39}}{52}
=-\frac{3\sqrt{39}}{13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{39}}{2*26}=\frac{0+12\sqrt{39}}{52}
=\frac{12\sqrt{39}}{52}
=\frac{3\sqrt{39}}{13}
$